3 ms·

That title though. Has anyone figured it out yet?

chatmasta 11y ago
I tried for a while but am having trouble with the offsets (and possibly the correct edition of the DOI). The smartest way to get the offsets correct would be to copy the numbers from the image and cross reference them with the decrypted text. But who's got time for that? :) Some Python code if anyone wants to play with it: words = doi.replace(',', ' ').replace('\n', ' ').replace(' ', ' ').replace(':', ' ').replace('.', ' ').replace("'", ' ').replace('"', ' ').replace(';', ' ').split(' ') words = filter(None, words) def getcode(w, i, offset): print w[i-offset][0], for code in [89, 263, 201, 500, 337, 480]: getcode(words, code, 0) I used http://www.constitution.org/usdeclar.txt http://www.constitution.org/usdeclar.txt and deleted the header and title.
- frogpelt 11y ago
  I tried that and got nothing. The numbers and text are here: (http://cipherfoundation.org/older-ciphers/beale-papers/beale-papers-transcription/ http://cipherfoundation.org/older-ciphers/beale-papers/beale...) Credit to kencausey
  - chatmasta 11y ago
    I think you're probably right on your lucky guess (I see you edited it out, so I'll suppress the spoiler alert as well :)). I was able to get something fairly close to that with variable offsets.
    - frogpelt 11y ago
      What text did you find it in?
      - chatmasta 11y ago
        I "roughly" got it using the DOI txt I linked above. I tried again with the pre-mapped text you linked to, and got `e o a p s p` which is an anagram for `appose`... perhaps that is the word? "Appose" means "to place (something) in proximity to or juxtaposition with something else." Maybe I'm grasping at straws here... Offset of +1 yields `b s a i t h` which is an anagram for habits. Offset of -1 yields `a t a l b t` which is an anagram for Alt-Tab (which is roughly what I'm doing right now to get out of this :p) I also tried all offsets within 0-7 for each character, to see if "CIPHER" could fit in that range. CI_H_R is possible but there is no P or E within +/- 7 offset of 201 or 337. Here's the python: txt="""<<Pasted from http://cipherfoundation.org/older-ciphers/beale-papers/beale-papers-transcription/>>""" import re codes = txt.split(' ') codes = filter(None, codes) code2word = {} words = [] for code in codes[0:-1]: try: index = re.search(re.compile(ur'\((\d+)\)'), code).group(1) except: index = index + 1 word = code.replace('(%d)' % int(index), '') code2word[int(index)] = word print index, word for code in [89, 263, 201, 500, 337, 480]: word = code2word[code] print word[0], Good luck
- cyanbane 11y ago
  I was using ps to try to find it real quick: At first tried the DOI: (Today's) DOI (Today) 89 "by" 263 "such" 201 "all" 500 "of" 337 "to" 480 "has" DOI (from Then) from earlier link: 89 / e 263 / o 201 / a 500 / p 337 / s 480 / p Didn't see anything, so then I tried the article text itself. There was an "and/or" combination that I didn't know how to space so I took word X-1, X, and X+1: 89 of / two / years 263 tantalizing mystery of 201 remained / stubbornly / undechipherd 500 "American" / Dollars / I 337 locked / them /inside 480 punctuation / added, / the 89 o/t/y 263 t/m/o 201 r/s/u 500 a/d/i 337 l/t/i 480 p/a/t Maybe that X+1 column is support to say "you d it?" Not sure. Having to divert attention now. Fun title though.
frogpelt 11y ago
So, from the comment at the bottom of the article I played around with the article itself a little more. If you separate the word innkeeper into two words you can get the following: 89 years 263 of 201 undeciphered 500 words 337 inside 480 numbers You Win.

I tried for a while but am having trouble with the offsets (and possibly the correct edition of the DOI). The smartest way to get the offsets correct would be to copy the numbers from the image and cross reference them with the decrypted text. But who's got time for that? :) Some Python code if anyone wants to play with it: words = doi.replace(',', ' ').replace('\n', ' ').replace(' ', ' ').replace(':', ' ').replace('.', ' ').replace("'", ' ').replace('"', ' ').replace(';', ' ').split(' ') words = filter(None, words) def getcode(w, i, offset): print w[i-offset][0], for code in [89, 263, 201, 500, 337, 480]: getcode(words, code, 0) I used http://www.constitution.org/usdeclar.txt http://www.constitution.org/usdeclar.txt and deleted the header and title.

frogpelt 11y ago
I tried that and got nothing. The numbers and text are here: (http://cipherfoundation.org/older-ciphers/beale-papers/beale-papers-transcription/ http://cipherfoundation.org/older-ciphers/beale-papers/beale...) Credit to kencausey
- chatmasta 11y ago
  I think you're probably right on your lucky guess (I see you edited it out, so I'll suppress the spoiler alert as well :)). I was able to get something fairly close to that with variable offsets.
  - frogpelt 11y ago
    What text did you find it in?
    - chatmasta 11y ago
      I "roughly" got it using the DOI txt I linked above. I tried again with the pre-mapped text you linked to, and got `e o a p s p` which is an anagram for `appose`... perhaps that is the word? "Appose" means "to place (something) in proximity to or juxtaposition with something else." Maybe I'm grasping at straws here... Offset of +1 yields `b s a i t h` which is an anagram for habits. Offset of -1 yields `a t a l b t` which is an anagram for Alt-Tab (which is roughly what I'm doing right now to get out of this :p) I also tried all offsets within 0-7 for each character, to see if "CIPHER" could fit in that range. CI_H_R is possible but there is no P or E within +/- 7 offset of 201 or 337. Here's the python: txt="""<<Pasted from http://cipherfoundation.org/older-ciphers/beale-papers/beale-papers-transcription/>>""" import re codes = txt.split(' ') codes = filter(None, codes) code2word = {} words = [] for code in codes[0:-1]: try: index = re.search(re.compile(ur'\((\d+)\)'), code).group(1) except: index = index + 1 word = code.replace('(%d)' % int(index), '') code2word[int(index)] = word print index, word for code in [89, 263, 201, 500, 337, 480]: word = code2word[code] print word[0], Good luck
cyanbane 11y ago
I was using ps to try to find it real quick: At first tried the DOI: (Today's) DOI (Today) 89 "by" 263 "such" 201 "all" 500 "of" 337 "to" 480 "has" DOI (from Then) from earlier link: 89 / e 263 / o 201 / a 500 / p 337 / s 480 / p Didn't see anything, so then I tried the article text itself. There was an "and/or" combination that I didn't know how to space so I took word X-1, X, and X+1: 89 of / two / years 263 tantalizing mystery of 201 remained / stubbornly / undechipherd 500 "American" / Dollars / I 337 locked / them /inside 480 punctuation / added, / the 89 o/t/y 263 t/m/o 201 r/s/u 500 a/d/i 337 l/t/i 480 p/a/t Maybe that X+1 column is support to say "you d it?" Not sure. Having to divert attention now. Fun title though.

frogpelt 11y ago

So, from the comment at the bottom of the article I played around with the article itself a little more. If you separate the word innkeeper into two words you can get the following: 89 years 263 of 201 undeciphered 500 words 337 inside 480 numbers You Win.