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And it is a poor choice to consider that in C++, because in here there already is a default non-compatible interpretation for their expression.
by restalis 11y ago
And it is a poor choice to consider that in C++, because in here there already is a default non-compatible interpretation for their expression.
- CyberDildonics 11y agoIt depends on the context. The pipe in a data flow sense will be working on data structures, a bitwise or will need to work on two plain data types.