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Chaotic functions of continuous real variables are not computable. Computable physics assumes a discrete lattice, which the universe is not proven to be.
by knughit 11y ago
Chaotic functions of continuous real variables are not computable. Computable physics assumes a discrete lattice, which the universe is not proven to be.
- drdeca 11y agoHm, I was not aware of that. What about for, uh... It occurs to me that I'm not exactly sure what a chaotic function of continuous real variables is. Is it like, one where iterating it gives chaotic results, or? What if, instead of variables over the reals, using variables over the computable reals?
- j2kun 11y agoThere's also no proof (or even evidence) that the universe is not discrete.
- Natanael_L 11y agoCan't find any proof of that claim. So far it seems more likely that all physical systems are computable. Although you may need infinite time to achieve perfect accuracy when computing them in a simulation, but matematically that's still computable. Computability makes no assumption on the geometry, only on the rules the system follows.