2 ms·
> And the implications for security would be huge because we would have to redefine what we mean by provable security, and then have to make some other arbitrar
by baddox 11y ago
> And the implications for security would be huge because we would have to redefine what we mean by provable security, and then have to make some other arbitrary distinction. Is n^100 secure, but n^99 not?
That doesn't sound right. After all, there's already an arbitrarily smooth continuum between polynomial-time and exponential-time algorithms. See quasipolymomial or sub-exponential algorithms.