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But then it's not really uniform, is it? That innocent instruction to 'pick a random number' is carrying a lot of conceptual baggage.
by idlewords 11y ago
But then it's not really uniform, is it? That innocent instruction to 'pick a random number' is carrying a lot of conceptual baggage.
- sidedishes 11y agoRight, though I don't think uniform is the necessary condition here. We only need a positive chance of picking an R so that f(A) and f(B) are on different sides of R, which isn't as much of a problem if we're picking R from (-1, 1).
- idlewords 11y agoThere's also the question of how the first two numbers were chosen; in other words, what it means that 'the numbers are completely arbitrary'. I can't math real good, but this is the part that smells fishy to me.
- aidenn0 11y agoSo long as you have a non-zero chance of your number "R" being between A and B, you have an advantage.