3 ms·
Or you could do this: phoneCallRegistry.callWithIdentifier(identifier)?.hangUp() The ? means that hangUp() will not be called if callWithIdentifier(identi
by peterkelly 11y ago
Or you could do this:
phoneCallRegistry.callWithIdentifier(identifier)?.hangUp()
The ? means that hangUp() will not be called if callWithIdentifier(identifier) returns nil.