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Yes, that's the standard approach, but I was wondering how that meshed with not having to declare types (maybe the answer is just, that's the one place where yo
by KenoFischer 11y ago
Yes, that's the standard approach, but I was wondering how that meshed with not having to declare types (maybe the answer is just, that's the one place where you have to - or that's disallowed), but I was curious.
- eru 11y agoIn Haskell, if you don't do anything weird, you don't have to declare types either in the norm case: it can all be inferred.