3 ms·
That C^2 factor is a bit of a problem. Calculate the mass equivalent of any reasonable amount of energy you intend to "throw" and you will be disappointed. In t
by wai1234 11y ago
That C^2 factor is a bit of a problem. Calculate the mass equivalent of any reasonable amount of energy you intend to "throw" and you will be disappointed. In the other direction, that c^2 term works pretty well (for atomic bombs anyway).
For the relationship of the mass-energy equation to the force exerted by radiation. see Wikipedia:
https://en.wikipedia.org/wiki/Radiation_pressure https://en.wikipedia.org/wiki/Radiation_pressure