3 ms·

Speaking as someone who has done quite a lot of work using languages with terse lambda syntax... ...that's just not ever an issue.

• sixbrx 11y ago
  i think the poster thinks that with the fat arrow definition, name becomes an implicitly called function wherever it is used. I wouldn't like that either. but, I dont know if thats really the case though (I dont know ceylon). I think that fat arrow line would just become a no op instead, creating a lambda and throwing it away immediately ("name" being the param name in the lambda and nothing more).
  • gavinking 11y ago
    It's just a getter. Lots of languages have getters.
    • sixbrx 11y ago
      Ah that makes sense, thanks. I missed the implicit "we're in a class definition" in the original post.