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The exact size doesn't matter nearly as much as the fact that it has a bounded size. That changes the algebraic structure your proof operates on — and proofs on
by pdpi 11y ago
The exact size doesn't matter nearly as much as the fact that it has a bounded size. That changes the algebraic structure your proof operates on — and proofs on finite fields are often either general or at least give you results that explicitly depend on the size of the underlying set.