4 ms·

Okay, I don't get this one: >>> False == False in [False] True

• julian37 11y ago
  Both "in" and "==" are comparison operators that can be chained and so it's interpreted as False == False and False in [False] https://twitter.com/marcusaureliusf/status/557948873009037312 https://twitter.com/marcusaureliusf/status/55794887300903731...
  • bpicolo 11y ago
    >>> 1 in [1] in [[1]] True
    • ubernostrum 11y ago
      Again, chained comparisons. For any comparison operator (comparison operators are <, >, ==, >=, <=, <>, !=, 'is', 'not', 'is not', 'in' and 'not in'): x (operator1) y (operator2) z is defined by the language as equivalent to (x (operator1) y) and (y (operator2) z) So 1 in [1] in [[1]] is equivalent to (1 in [1]) and ([1] in [[1]]) For any comparison operator
      • tcdent 11y ago
        Though, according to the docs, `y` in your first example is only evaluated once when using the shorthand chained method.
      • bpicolo 11y ago
        Right. I was giving another example that might make it more clear : P
• tcdent 11y ago
  I tend to write complex conditionals with parenthesis, sometimes excessively, but the clarity and guarantee of correct evaluation far outweighs any brevity. >>> False == (False in [False, ]) False