3 ms·
The opposite is true. In Perl 5 passing a hash to a function requires mallocing a new shallow copy of that hash. In Perl 6 this would be the equivalent of passi
by baudehlo 11y ago
The opposite is true. In Perl 5 passing a hash to a function requires mallocing a new shallow copy of that hash. In Perl 6 this would be the equivalent of passing a reference to the hash, which would only require mallocing a scalar.