3 ms·
I was also lost at that part, although for a different reason. The function f was assumed to be from R to R, so it does not make formal sense to plug in f(x+ih)
by mbroshi 11y ago
I was also lost at that part, although for a different reason. The function f was assumed to be from R to R, so it does not make formal sense to plug in f(x+ih).
I guess the author has the unstated assumption that f is the restriction to R of a function on C.
- eriktaubeneck 11y agoGreat point, and I apologize for the confusion. The function should be C to C, with the added restriction of R to R.