4 ms·
Not if it's a cube: Volume = 1e-4 ^ 3 = 1e-12 m^3 Assume density 1kg/l Mass = 1e-9kg Velocity = 8000m/s KE = 0.032J Mass of bullet (https://en.wikipedia.org/w
by Jabbles 11y ago
Not if it's a cube:
Volume = 1e-4 ^ 3 = 1e-12 m^3
Assume density 1kg/l
Mass = 1e-9kg
Velocity = 8000m/s
KE = 0.032J
Mass of bullet (https://en.wikipedia.org/wiki/Physics_of_firearms https://en.wikipedia.org/wiki/Physics_of_firearms)
A .44 Remington Magnum with a 240-grain (0.016 kg) ...(360m/s)
Which has 1036.8J of kinetic energy.
So the ratio is actually about 32400 in favor of the bullet. But note that this will change with the cube of the size mentioned, so even though this is exaggerated, a fleck of paint 3mm across would make the quote reasonably accurate.