3 ms·
Sure. But I might write my n:1 code more quickly, robustly, and performant than your m:n code, since m:n forces the programmer to carefully worry about whether
by sillysaurus3 11y ago
Sure. But I might write my n:1 code more quickly, robustly, and performant than your m:n code, since m:n forces the programmer to carefully worry about whether their code will break.
- theseoafs 11y agoMaybe, if my program has a lot of shared mutable state. I'm smart enough to avoid that though.