There's no hashing construction that will "completely eliminate the possibility" (see https://en.wikipedia.org/wiki/Pigeonhole_principle https://en.wikipedia.or

There's no hashing construction that will "completely eliminate the possibility" (see https://en.wikipedia.org/wiki/Pigeonhole_principle https://en.wikipedia.org/wiki/Pigeonhole_principle), so I'm not sure what answer you're looking for. It's computationally infeasible to generate collisions (accidental or malicious) if SHA-2 is not broken. If you're interested in reading about how combining multiple hashes affects security, see this paper: https://www.iacr.org/cryptodb/archive/2004/CRYPTO/1472/1472.pdf https://www.iacr.org/cryptodb/archive/2004/CRYPTO/1472/1472....