3 ms·
Close; two minor details though. 1. A = k*B^C. We can have an arbitrary constant k in there. 2. 10^N > A > 10^(N+D). That is, A need not be small, it just has
by monochromatic 11y ago
Close; two minor details though.
1. A = k*B^C. We can have an arbitrary constant k in there.
2. 10^N > A > 10^(N+D). That is, A need not be small, it just has a constrained range.
The "goes as" language is common, but a little loose/imprecise.
- msvan 11y agoThanks!