4 ms·
... unless you start with zero customers :)
by woid 17y ago
... unless you start with zero customers :)
- idlewords 17y agoSeems eminently more achievable in that case.
- allantyoung 17y agoOr infinitely more achievable.
- tokenadult 17y agoLESS achievable. Multiplication by zero still gives a product of zero in the real number system.
- frisco 17y ago>> Multiplication by zero still gives a product of zero in the real number system. Yeah which is why its more achievable: factor = final / initial = 3 customers / 0 customers = ZOMGx more customers
- tokenadult 17y agoAh, the usual division by zero error. http://en.wikipedia.org/wiki/Division_by_zero http://en.wikipedia.org/wiki/Division_by_zero http://mathforum.org/dr.math/faq/faq.divideby0.html http://mathforum.org/dr.math/faq/faq.divideby0.html http://www.math.utah.edu/~pa/math/0by0.html http://www.math.utah.edu/~pa/math/0by0.html http://mathworld.wolfram.com/DivisionbyZero.html http://mathworld.wolfram.com/DivisionbyZero.html Perhaps more to my original point is that cperciva replied to the thread-opening post I plan to end 2010 with 10x as many customers as I start it with. so the the comment by woid (grandchild comment to cperciva's comment) is CORRECT that such a goal is not achievable if you start with zero customers because there isn't any defined number of customers that is exactly ten times as many customers as zero customers. It's funny that this isn't taught in all mathematics classes.
- frisco 17y agoI understand the math; sure, 10*0=0. Looking lim a->0: x/a, though, which goes to infinity, I was implying it was easier to achieve because mathematically he'd be way past his target of 10x. But you're right that it's impossible to hit exactly 10x.