Sum of products is surprisingly hard to do for something like ammonium nitrate. Among other things, there are actually multiple distinct breakdowns: NH4

Sum of products is surprisingly hard to do for something like ammonium nitrate. Among other things, there are actually multiple distinct breakdowns: NH4NO3 ----> HNO3 + NH3 5 NH4NO3 ----> 2 HNO3 + 9 H2O + 4 N2 2 NH4NO3 ----> O2 + 4 H2O + 2 N2 NH4O3 ----> N2O + 2 H2O I suspect you could do fairly well by assuming that it follows reaction 3, though. Like with assuming complete combustion.