3 ms·
Curious that he couldn't "find" the enthalpy of reaction for the ammonium nitrate. Surely he could calculate it from the sum of the products minus the sum of th
by dbcooper 11y ago
Curious that he couldn't "find" the enthalpy of reaction for the ammonium nitrate. Surely he could calculate it from the sum of the products minus the sum of the reactants.
- TheLoneWolfling 11y agoSum of products is surprisingly hard to do for something like ammonium nitrate. Among other things, there are actually multiple distinct breakdowns: NH4NO3 ----> HNO3 + NH3 5 NH4NO3 ----> 2 HNO3 + 9 H2O + 4 N2 2 NH4NO3 ----> O2 + 4 H2O + 2 N2 NH4O3 ----> N2O + 2 H2O I suspect you could do fairly well by assuming that it follows reaction 3, though. Like with assuming complete combustion.