> For multiplication, I think the math works out the same for unsigned and signed, within mod bit-size and you throw away the "overflow"? Yeah, true. I recalle

> For multiplication, I think the math works out the same for unsigned and signed, within mod bit-size and you throw away the "overflow"? Yeah, true. I recalled there being separate instructions and then messed up my napkin math to check if it made a difference within the relevant range.