2 ms·
Given there are no exponent bits (all of the bits are effectively mantissa bits with no hidden bit), your plan doesn't seem to make sense. The numbers are (int
by Veedrac 11y ago
Given there are no exponent bits (all of the bits are effectively mantissa bits with no hidden bit), your plan doesn't seem to make sense.
The numbers are (integer_value * 2 ^ constant_exponent), such that all bits are dedicated to integer_value.