3 ms·
Actually, you can write: foo = (\a -> \b -> (a+b)*(a-b)) :: Num z => z -> z -> z HOwever, it is quite un-idiomatic, of course.
by voxfrege 11y ago
Actually, you can write:
foo = (\a -> \b -> (a+b)*(a-b)) :: Num z => z -> z -> z
HOwever, it is quite un-idiomatic, of course.