3 ms·
That's not true. Unsigned wrap is well-defined and wraps around to 0. Signed wrap is undefined.
by banachtarski 11y ago
That's not true. Unsigned wrap is well-defined and wraps around to 0. Signed wrap is undefined.
- cautious_int 11y agoIt is not true that unsigned wrap is defined? Did you even read my comment, here is the relevant part: unsigned wrap is defined