But not into a register right? Given my (flawed) assumption that there would be two reads, whilst the first might load the second into the cache, it wouldn't lo

But not into a register right? Given my (flawed) assumption that there would be two reads, whilst the first might load the second into the cache, it wouldn't load into a register without another instruction telling it to. This costs a lot less than the cache fetch but it still has a cost.