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It kinda bothers me when in his presentation Raymond says make NP P. A problem is and have always been in P if there is an algorithm for the problem that solves
by antimora 11y ago
It kinda bothers me when in his presentation Raymond says make NP P. A problem is and have always been in P if there is an algorithm for the problem that solves in polynomial time. You can have an algorithm for the same problem that does not solve in polynomial time but this does not change the nature of the problem.
- Lord_DeathMatch 11y agoT'was a joke; Non-Pythonic vs Pythonic (NP v P)