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The numerator is equivalent to (x-1.5)*(x-1). Cancel out the (x-1.5) from numerator and denominator, leaving x - 1 > 0. I'm not sure what the point of the po
by ambition 17y ago
The numerator is equivalent to (x-1.5)*(x-1).
Cancel out the (x-1.5) from numerator and denominator, leaving x - 1 > 0.
I'm not sure what the point of the post is, or why the discussions here are using so many words I don't understand.
- ajscherer 17y agoType these two expressions into a calculator or spreadsheet: ((1.5 - 1.5) * (1.5 - 1))/(1.5 - 1.5) (1.5 - 1) Did you get the same answer? If not then there must either a bug in your calculator/spreadsheet or in wolfram alpha.
- teilo 17y agoWrong. You are invoking division by zero to prove what, exactly? 0.5 * 0 / 0 = 0.5 Excel or your calculator will freak out, but it's still true.
- dagw 17y ago(0.5 * 0)/0 does not in any way equal 0.5 (assuming real numbers and all normal definition of operators). Sure the limit of (0.5 * x)/x =0.5 as x->0, but that is not the same thing.
- teilo 17y agoThis is then my ignorance showing, in that I made a classic blunder of accepting the premise of division by zero in a test case. What I should have said is that if you intentionally craft the circumstances of an equation such that you are dividing by zero, it is your premise that is nonsense, NOT the equation itself.
- teilo 17y agoNow, interestingly, Wolfram Alpha does not agree with you: http://www.wolframalpha.com/input/?i=xy/y+where+y%3D0+and+x+%3D+0.5 http://www.wolframalpha.com/input/?i=xy/y+where+y%3D0+and+x+...