3 ms·
That depends on your clustering algorithms. If it is for example based on shared-neighbor information, then you end up with the same clusters as you did before
by codingbinary 11y ago
That depends on your clustering algorithms. If it is for example based on shared-neighbor information, then you end up with the same clusters as you did before scaling.
And in your example, I get: (A, B) < (B, C) < (A, C) before
and (A, B) < (B, C) < (A, C) after scaling.
So the order is preserved. It really depends on your clustering algorithm. DBSCAN for example could end up with a different result due to its epsilon-range parameter.